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(3x-7)^(2)-4(3x-7)-12=0
We multiply parentheses
(3x-7)^2-12x+28-12=0
We add all the numbers together, and all the variables
-12x+(3x-7)^2+16=0
We move all terms containing x to the left, all other terms to the right
-12x+(3x-7)^2=-16
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